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Home/ Questions/Q 3343048
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T00:54:35+00:00 2026-05-18T00:54:35+00:00

I have a custom listview in which one textview and one checked box is

  • 0

I have a custom listview in which one textview and one checked box is in each row.
When I click the ckeckbox, I want to add the value from TextView to database and to display a Toast message in the view. The database insertion is working fine. But the application is stopping suddently, and the Toast message is not shown in the view.

 public class Favourites extends Activity 
 {
     @Override
     public void onCreate(Bundle savedInstanceState)
     {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main_list);
        ListView listitems = (ListView) findViewById(R.id.ListView_01);
        listitems.setAdapter(new EfficientAdapter(this));
     }
     private static class EfficientAdapter extends BaseAdapter
     {
        //imp
        public View getView(int position,  View convertView, ViewGroup parent) 
        {

              if (convertView == null)
              {
                  int itemId=SubListIdList.get(position);
                  TextView text = (TextView) convertView.findViewById(R.id.TextView_02);
                  CheckBox star = (CheckBox) convertView.findViewById(R.id.star);
                  star.setOnCheckedChangeListener(new OnCheckedChangeListener() 

                  {

                       @Override
                       public void onCheckedChanged(CompoundButton buttonView,boolean isChecked)
                       {
                           Favourites f=new Favourites();
                           query="UPDATE "+SUB_TABLE_NAME+" SET FavoriteIndicator='Y' WHERE SubListID="+itemId;
                           db.execSQL(query);   
                           Toast.makeText(f, "Insertion successfull!", 1).show();
                       }
                 }
           }
       }
    }
}

Please help me…. Thank you…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T00:54:36+00:00Added an answer on May 18, 2026 at 12:54 am

    Give the Toast notification your main activitiy’s context to display it. I’m not quite sure why you are instantiating your activity again in the onCheckedChanged() method but I guess you were trying to pass your Toast a context with that. Try it this way.

    Context ctx = null;
    
    onCreate(Bundle bundle) {
        super.onCreate(bundle);
        // more stuff
        ctx = getApplication();
    
        // even more stuff
        @Override
        public void onCheckedChanged(CompoundButton buttonView,boolean isChecked) {
            query="UPDATE "+SUB_TABLE_NAME+" SET FavoriteIndicator='Y' WHERE" +
            " SubListID="+itemId;
            db.execSQL(query);   
            Toast.makeText(ctx, "Insertion successfull!", 4000).show();
        }
    }
    

    And please don’t set your Toast display time to one millisecond that won’t help you. The time parameters is set in milliseconds.

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