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Home/ Questions/Q 7820633
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T07:22:28+00:00 2026-06-02T07:22:28+00:00

I have a custom UISplitViewController, created so I can present a login screen to

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I have a custom UISplitViewController, created so I can present a login screen to the user. In this controller I also have a logout method.

The logout button is in the navigation bar of the MasterViewController. When the user clicks logout, I am trying to call the UISplitViewControllers logoutUser method. First I tried:

[self.splitViewController logoutUser:self];

This gave errors when trying to compile:

No visible @interface for ‘UISplitViewController’ declares the selector ‘logoutUser:’
I then commented out the offending line and added the following if, checking to see if indeed my UISplitViewController responds to the selector.

if([self.splitViewController respondsToSelector:@selector(logoutUser:)]){
   // [self.splitViewController logoutUser:self];
    NSLog(@"Selector");
}else{
    NSLog(@"No Selector");
}

In the log when running I get Selector. uncommenting the [self.splitViewController logoutUser:self] I get the same error.

I tried to clean the build and rebuild but it still gives this error. How cna I resolve this issue?

Thanks,
Bruce

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  1. Editorial Team
    Editorial Team
    2026-06-02T07:22:30+00:00Added an answer on June 2, 2026 at 7:22 am

    As commented above, I found the answer:

     [self.splitViewController performSelector:@selector(logoutUser:) withObject:self];
    
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