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Home/ Questions/Q 694953
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T02:54:34+00:00 2026-05-14T02:54:34+00:00

I have a data.frame from this code: my_df = data.frame(read_time = c(2010-02-15, 2010-02-15, 2010-02-16,

  • 0

I have a data.frame from this code:

   my_df = data.frame("read_time" = c("2010-02-15", "2010-02-15", 
                                      "2010-02-16", "2010-02-16", 
                                       "2010-02-16", "2010-02-17"), 
                      "OD" = c(0.1, 0.2, 0.1, 0.2, 0.4, 0.5) )

which produces this:

> my_df
   read_time  OD
1 2010-02-15 0.1
2 2010-02-15 0.2
3 2010-02-16 0.1
4 2010-02-16 0.2
5 2010-02-16 0.4
6 2010-02-17 0.5

I want to average the OD column over each distinct read_time (notice some are replicated others are not) and I also would like to calculate the standard deviation, producing a table like this:

> my_df
   read_time  OD        stdev
1 2010-02-15 0.15       0.05
5 2010-02-16 0.3         0.1
6 2010-02-17 0.5         0

Which are the best functions to deal with concatenating such values in a data.frame?

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  1. Editorial Team
    Editorial Team
    2026-05-14T02:54:35+00:00Added an answer on May 14, 2026 at 2:54 am

    The plyr package is popular for this, but the base functions by() and aggregate() will also help.

    > ddply(my_df, "read_time", function(X) data.frame(OD=mean(X$OD),stdev=sd(X$OD)))
       read_time      OD   stdev
    1 2010-02-15 0.15000 0.07071
    2 2010-02-16 0.23333 0.15275
    3 2010-02-17 0.50000      NA
    

    You can add the missing bit to return 0 instead of NA for the last std.dev.

    Also, you don’t need the quotes (on the variables) you had in the data.frame construction.

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