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Home/ Questions/Q 3273926
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T18:59:00+00:00 2026-05-17T18:59:00+00:00

I have a data.frame ( link to file ) with 18 columns and 11520

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I have a data.frame (link to file) with 18 columns and 11520 rows that I transform like this:

library(plyr)
df.median<-ddply(data, .(groupname,starttime,fPhase,fCycle), 
                 numcolwise(median), na.rm=TRUE)

according to system.time(), it takes about this long to run:

   user  system elapsed 
   5.16    0.00    5.17

This call is part of a webapp, so run time is pretty important. Is there a way to speed this call up?

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  1. Editorial Team
    Editorial Team
    2026-05-17T18:59:00+00:00Added an answer on May 17, 2026 at 6:59 pm

    Just using aggregate is quite a bit faster…

    > groupVars <- c("groupname","starttime","fPhase","fCycle")
    > dataVars <- colnames(data)[ !(colnames(data) %in% c("location",groupVars)) ]
    > 
    > system.time(ag.median <- aggregate(data[,dataVars], data[,groupVars], median))
       user  system elapsed 
       1.89    0.00    1.89 
    > system.time(df.median <- ddply(data, .(groupname,starttime,fPhase,fCycle), numcolwise(median), na.rm=TRUE))
       user  system elapsed 
       5.06    0.00    5.06 
    > 
    > ag.median <- ag.median[ do.call(order, ag.median[,groupVars]), colnames(df.median)]
    > rownames(ag.median) <- 1:NROW(ag.median)
    > 
    > identical(ag.median, df.median)
    [1] TRUE
    
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