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Home/ Questions/Q 6928481
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T11:11:37+00:00 2026-05-27T11:11:37+00:00

I have a data.frame with 2 columns dates=dates of observations for each station and

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I have a data.frame with 2 columns dates=dates of observations for each station and values=observation data

> head(dataset.a)

     dates      values
1 1976-01-01       7.5
2 1976-01-02        NA
3 1976-01-03        NA
4 1976-01-04        NA
5 1976-01-05        NA
6 1976-01-06      10.2
(...)

I have to multiply each row by a value that I have already from another data.frame:

> head(dataset.b)

     dates      values
1 1976-01-01      0.23
2 1976-01-02        NA
3 1976-01-03        NA
4 1976-01-04        NA
5 1976-01-05        NA
6 1976-01-06      1.23
(...)

Both datasets contain the Gregorian Calendar, however the dataset.a contains
Leap years (adds a 29th day to February) and the dataset.b has always 28 days in February. I want to ignore all 29th days of February in dataset.a and make the multiplication.

I should be able to make a basic subset using both indices:

which(strftime(dataset.a[,1],"%d")!="29")
which(strftime(dataset.a[,1],"%m")!="02")

However once I add a logical AND I loose the position in the data.frame were I have YEAR-02-29 and he returns me the number of rows that are TRUE for the combination of both indices.

I guess this is a very basic question, but I am lost.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T11:11:38+00:00Added an answer on May 27, 2026 at 11:11 am

    Try a logical index:

    idx <- strftime(ws.hb1.dataset[d,1],"%d")!="29" & strftime(ws.hb1.dataset[d,1],"%m")!="02"
    

    Note: I’m assuming ws.hb1.dataset[d,1] is basically dataset.a[,1] here?

    Then you’ll get a vector of TRUE TRUE ... TRUE FALSE TRUE TRUE .. with the FALSE coinciding with 29/Feb.

    Then you can just do dataset.a[idx,] to get the non 29/Feb dates.

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