Question

I have a data frame with several factor columns containing NaN‘s that I would like to convert to NA‘s (the NaN seems to be a problem for using linear regression objects to predict on new data).

> tester1 <- c("2", "2", "3", "4", "2", "3", NaN)
> tester1 
[1] "2"   "2"   "3"   "4"   "2"   "3"   "NaN"
> tester1[is.nan(tester1)] = NA
> tester1 
[1] "2"   "2"   "3"   "4"   "2"   "3"   "NaN"
> tester1[is.nan(tester1)] = "NA"
> tester1 
[1] "2"   "2"   "3"   "4"   "2"   "3"   "NaN"

Answer 1

Here’s the problem: Your vector is character in mode, so of course it’s “not a number”. That last element got interpreted as the string “NaN”. Using is.nan will only make sense if the vector is numeric. If you want to make a value missing in a character vector (so that it gets handle properly by regression functions), then use (without any quotes), NA_character_.

> tester1 <- c("2", "2", "3", "4", "2", "3", NA_character_)
>  tester1
[1] "2" "2" "3" "4" "2" "3" NA 
>  is.na(tester1)
[1] FALSE FALSE FALSE FALSE FALSE FALSE  TRUE

Neither “NA” nor “NaN” are really missing in character vectors. If for some reason there were values in a factor variable that were “NaN” then you would have been able just use logical indexing:

tester1[tester1 == "NaN"] = "NA"  
# but that would not really be a missing value either 
# and it might screw up a factor variable anyway.

tester1[tester1=="NaN"] <- "NA"
Warning message:
In `[<-.factor`(`*tmp*`, tester1 == "NaN", value = "NA") :
invalid factor level, NAs generated
##########
tester1 <- factor(c("2", "2", "3", "4", "2", "3", NaN))

> tester1[tester1 =="NaN"] <- NA_character_
> tester1
[1] 2    2    3    4    2    3    <NA>
Levels: 2 3 4 NaN

That last result might be surprising. There is a remaining “NaN” level but none of elements is “NaN”. Instead the element that was “NaN” is now a real missing value signified in print as .