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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T09:56:07+00:00 2026-05-13T09:56:07+00:00

I have a database containing records collected every 0.1 seconds, and I need to

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I have a database containing records collected every 0.1 seconds, and I need to time-average the data from a given day to once every 20 minutes. So I need to return a day’s worth of data averaged to every 20 minutes which is 24*3 values.
Currently I do a separate AVG call to the database for each 20-minute period within the day, which is 24*3 calls. My connection to the database seems a little slow (it is remote) and it takes ~5 minutes to do all the averages. Would it be faster to do a single query in which I access the entire day’s worth of data then average it to every 20 minutes? If it helps to answer the question, I have to do some arithmetic to the data before averaging, namely multiplying several table columns.

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  1. Editorial Team
    Editorial Team
    2026-05-13T09:56:08+00:00Added an answer on May 13, 2026 at 9:56 am

    You can calculate the number of minutes since midnight like:

    datepart(hh,datecolumn)*60 + datepart(mi,datecolumn)
    

    If you divide that by 20, you get the number of the 20 minute interval. For example, 00:10 would fall in interval 0, 00:30 in interval 1, and 15:30 in interval 46, and so on. With this formula, you can group on 20 minute intervals like:

    select
        (datepart(hh,datecolumn)*60 + datepart(mi,datecolumn)) / 20 as IntervalNr
    ,   avg(value)
    from      YourTable
    group by  (datepart(hh,datecolumn)*60 + datepart(mi,datecolumn)) / 20
    

    You can do math inside the avg call, like:

    avg(col1 * col2 - col3 / col4)
    
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