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Home/ Questions/Q 9269015
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T15:00:14+00:00 2026-06-18T15:00:14+00:00

I have a database (i use MS ACCESS) I have this insert code, I

  • 0

I have a database (i use MS ACCESS) I have this insert code, I can read data but got error when writing, I follow instruction but it didn’t work
here is my code

OleDbConnection con = new OleDbConnection(@" provider=Microsoft.ace.Oledb.12.0; data source=\\sisc-erelim\4_Printing\VTDB\DB\VirginiTEADB2.accdb; Persist Security Info=False");

private void button1_Click(object sender, EventArgs e)
        {
            try
            {
                OleDbCommand cmd = new OleDbCommand();
                cmd.CommandType = CommandType.Text;
                cmd.CommandText = "INSERT INTO Accountstbl (Username, Password)" + "VALUES ('" + textBox1.Text + "','" + textBox2.Text + "')";
                cmd.Parameters.AddWithValue("@Username", textBox1.Text);
                cmd.Parameters.AddWithValue("@Password", textBox2.Text);
                cmd.Connection = con;
                con.Open();
                cmd.ExecuteNonQuery();
            }
            catch (Exception ex)
            {
                textBox1.Text = ex.ToString();
            }

And I always got this error,

System.Data.OleDb.OleDbException: Syntax error in INSERT INTO statement.
   at System.Data.OleDb.OleDbCommand.ExecuteCommandTextErrorHandling(OleDbHResult hr)
   at System.Data.OleDb.OleDbCommand.ExecuteCommandTextForSingleResult(tagDBPARAMS dbParams, Object& executeResult)
   at System.Data.OleDb.OleDbCommand.ExecuteCommandText(Object& executeResult)
   at System.Data.OleDb.OleDbCommand.ExecuteCommand(CommandBehavior behavior, Object& executeResult)
   at System.Data.OleDb.OleDbCommand.ExecuteReaderInternal(CommandBehavior behavior, String method)
   at System.Data.OleDb.OleDbCommand.ExecuteNonQuery()
   at VirginiTEAcorp.Form3.button1_Click(Object sender, EventArgs e) in C:\Documents and Settings\12-014s\My Documents\applications\Database\WindowsFormsApplication1\Form3.cs:line 34
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T15:00:16+00:00Added an answer on June 18, 2026 at 3:00 pm

    You defined @Username and @Password parameters but you never used in your sql command.

    How about?

    cmd.CommandText = "INSERT INTO Accountstbl (Username, [Password]) VALUES (@Username, @Password)";
    cmd.Parameters.AddWithValue("@Username", textBox1.Text);
    cmd.Parameters.AddWithValue("@Password", textBox2.Text);
    cmd.Connection = con;
    con.Open();
    cmd.ExecuteNonQuery();
    

    Also you should use Password in square brackets on your sql command like [Password] because it is a reserved keyword in MS Access.

    If you don’t this can cause an error like;

    Incorrect syntax near the keyword “Password”

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