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Editorial Team
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Asked: 2026-05-30T04:15:00+00:00

I have a database (SQL) with the table Staff with two records in it.

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I have a database (SQL) with the table “Staff” with two records in it. I am required to display the contents of these records on a web page using PHP.

<html>
<head>
<title>CES Staff details</title>
</head>

<body>

**code emitted**

<?php
$row = mysql_fetch_array($result) ; 
$looping = 1;
$i = $row.length;
while ($looping <= $i)  
    {
        echo $row["Name"].", Room ".$row["Room"].", Tel ".$row["Telephone"] ;
        $looping++;
    }
?>
</body>
</html>

How would I change the while loop correctly so that it will display both records on the page.

Thanks!

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1 Answer

  1. Editorial Team

    mysql_fetch_array() only retrieves a single row from the database. You need to call it inside your while loop to retrieve all rows. The $looping increment is unnecessary here, since mysql_fetch_array() returns false when no more rows are available.

    while ($row = mysql_fetch_array($result))  
{
    echo $row["Name"].", Room ".$row["Room"].", Tel ".$row["Telephone"] ;
}
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