Question

I have a database that contains rows with links to each episode in them. I am trying to use the below code to get all the links for one type of show and I manage to do that successfully. What I can’t seem to figure out is how I can get just one of the rows to display rather then having them all display in a single line of text so I could use them in building my page.

$query = "SELECT direct_link FROM episode_link WHERE anime_id = '$animeid'";
$result = mysql_query($query) or die(mysql_error());    
while($row = mysql_fetch_array($result)) 
{
    $dlink = $row['direct_link'];
    echo $dlink;
}

Currently it’s displaying them all like this.

link1link2link3link4link5link6

I would like to be able to display them one at a time or put assign variables to them so I can put them in href tags on my site. I thought I could do this by using $row[1] but that does not display anything.

Sorry if I made it hard to understand, new to php so I am still learning.

Answer 1

I suggest you look up some basic tutorial sites abit more

$dlink = array();
while($row = mysql_fetch_array($result)){
        $dlink[] = $row['direct_link'];
}

then when you want to echo out:

foreach($dlink as $link){
echo '<a href="'.$link.'">'.$link.'</a><br />'.PHP_EOL;
}

---

Also: as you may want the title of the link and not a literal link, you should grab the title from the database too, if you have stored it that is:

SELECT direct_link,title FROM episode_link...

$dlink = array();
$i=0;
while($row = mysql_fetch_array($result)){
        $dlink[$i]['title'] = $row['title'];
        $dlink[$i]['link']  = $row['direct_link'];
$i++;
}

Then when echoing out:

foreach($dlink as $link){
echo '<a href="'.$link['link'].'">'.$link['title'].'</a><br />'.PHP_EOL;
}