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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T15:11:13+00:00 2026-05-15T15:11:13+00:00

I have a database with 2 tables CD and Song . Session bean access

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I have a database with 2 tables CD and Song. Session bean access then entity classes of those two tables. In my backing bean, I just have a String cd and HashMap<CDName, CDName> cds that will hold the list of CD return back from my sessionbean, so in JSF I would do something like this.

<h:selectOneMenu id="cd" value="#{backingBean.cd}">
     <f:selectItem itemLabel="Select CD" itemValue="" />
     <f:selectItems value="#{backingBean.cds}" />
</h:selectOneMenu>

This successfully load a list of cd onto the drop down list, and if I select a cd, cd variables would hold the name of the CD I select. This work great if CDName is unique. But unfortunately it is not. So what I want is HashMap<ID, CDName> cds where ID is the PK in table CD. But now how I can set it up, so when I click on a item from the CD drop down list, I get the ID back in my backingbean, so that I can do something like this, in my session bean

CD cd = EntityManager.find(CD.class, the id that I get back from JSF page)

essentially I want to obtain the cd object that I just click on, keep it in mind, there might be duplication. If my design is bad, please point out. Help please. Thanks in advance

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  1. Editorial Team
    Editorial Team
    2026-05-15T15:11:13+00:00Added an answer on May 15, 2026 at 3:11 pm

    It will be set in the property behind #{backingBean.cd} as illustrated in your code example.

    So, basically:

    CD cd = em.find(CD.class, this.cd);
    

    Alternatively, you can also have a HashMap<CD, CDName> instead and use a javax.faces.convert.Converter which does basically the following:

    public Object getAsObject(FacesContext context, UIComponent component, String value) {
        return em.find(CD.class, value);
    }
    
    public String getAsString(FacesContext context, UIComponent component, Object value) {
        return String.valueOf(((CD) value).getId());
    }
    

    See also:

    • Objects in h:selectOneMenu.

    That said, a HashMap is by nature unordered. Are you sure you don’t rather need a TreeMap (automatic sort by key) or a LinkedHashMap (insertion order)?

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