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Home/ Questions/Q 3439434
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T08:18:36+00:00 2026-05-18T08:18:36+00:00

I have a database with a table which includes among others, one column of

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I have a database with a table which includes among others, one column of dates (the column is titled ‘date’) in the format of Y-m-d.

I want to extract all the rows of data which have been logged during the current month, so I am using the following query:

$year_month = date("Y-m");
$query = "SELECT date FROM tracker WHERE date LIKE '$year_month%'";

When I execute the query and attempt to output it visually, I get the error “Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource on line 64”.

Line 64 is the beginning of the following loop:

while($row = mysql_fetch_array($result, MYSQL_ASSOC)
{
    echo "Name :{$row['date']} <br>";
}

I’ve scoured google and had a look here too, but I can’t seem to figure out this seemingly simple problem. As far as I can tell, the actual query is executing just fine.

Any ideas?

** Additional – Call to MySQL Query Below **

$result = mysqli_query($conn, $query);

$conn refers to the following line:

$conn = @mysqli_connect($dbhost, $dbuser, $dbpass, $dbname) or die ('Error connecting to MySQL');
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  1. Editorial Team
    Editorial Team
    2026-05-18T08:18:36+00:00Added an answer on May 18, 2026 at 8:18 am

    Two things jump out at me:

    1. Are you sure that’s the query that goes with that result? Queries like insert and delete do not have results. They return a boolean indicating success.

    2. Are you checking to make sure the query succeeded? After the line where you call mysql_query, make sure you check the result. If it’s false, you can call mysql_get_error to find out what went wrong.

    EDIT: Okay, your real problem is that you’re mixing mysql_* and mysqli_* commands. You need to use one or the other.

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