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Home/ Questions/Q 6836237
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T23:19:55+00:00 2026-05-26T23:19:55+00:00

I have a database with a vertical schema, explained: Key, Cat, UID, Var, Val,

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I have a database with a vertical schema, explained:

Key, Cat, UID, Var, Val, etc…
Where Key is the index, Cat is the category, UID is the identifier for a group of rows, var is the name of the value the row represents and Val is that value. So a few rows would look something like this:

key cat   uid    var          val
 1   1   98765  name         David
 2   1   98765  description  handsome, young, sporting, 
 3   1   98765  phone        123-456-789
 4   1   98765  email        david@handsome.com
 5   1   12345  name         Jason
 6   1   12345  description  cool, hot, tall, 
 7   1   12345  phone        222-555-1244
 8   1   12345  email        jason@cool.org
 8   1   12345  website      www.jason.com

So the goal with the query/php is to get all rows from a specified category, then return an associative array based on the uid for all the rows with that uid. The result would be somehting like

results{
["98765"] => ["name"] = David
          => ["description"] = handsome, young, sporting,
          => ["phone"] = 123-456-789
          => ["email"] = david@handsome.com
["12345"] => ["name"] = Jason
          => ["description"] = cool, hot, tall,
          => ["phone"] = 222-555-1244
          => ["email"] = jason@cool.org
          => ["website"] = www.jason.com
}

Hopefully that’s understandable, let me know if my question is unclear.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T23:19:56+00:00Added an answer on May 26, 2026 at 11:19 pm

    Try something like this:

    $category = 1;
    $result = mysql_query( 'SELECT * FROM table WHERE cat = ' . intval( $category));
    $results = array();
    while( $row = mysql_fetch_array( $result))
    {
        $results[ $row['uid'] ][ $row['var'] ] = $row['val'];
    }
    mysql_free_result( $result);
    
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