Question

I have a database with structure

TableName | Row1 | Row2 | Row3 ...etc

My ‘Row’ table column goes up quite high, I wanted to try to query the database and use a variable in the row name to return my value, except it keeps returning NULL values, probably because it isn’t actually returning anything

<?php
    $connection = mysqli_connect(....);

    $sql = "SELECT * FROM table";
    $result = $connection->query($sql);
    if($result) {
        while($row = $result->fetch_object()) {
            for($i = 1; $i < 5; $i++) {
                echo $row->Row.$i;
            }
        }
    }
?>

I thought this would be the code but it doesnt work like this, currently I have the code set to

for(...
    $myrow = 'Row'.$i;
    echo $row->$myrow;
}

Which works although its a little sloppy and I assume there is a much nicer way of doing it

Answer 1

Perhaps this is what you mean:

$row->{'Row'.$i};

Not sure if I understood the question correctly, though,