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Home/ Questions/Q 6935669
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T12:07:58+00:00 2026-05-27T12:07:58+00:00

I have a dataframe with four logical vectors, v1 , v2 , v3 ,

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I have a dataframe with four logical vectors, v1, v2, v3, v4 that are TRUE or FALSE. I need to classify each row of the dataframe based on the combination of the boolean vectors (for example, “None”, “v1 only”, “v1 and v3”, “All”, etc.). I would like to do this without taking a subset of the dataframe or nesting ifelse statements.
Any suggestions for the best way to do this? Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-27T12:07:59+00:00Added an answer on May 27, 2026 at 12:07 pm

    Looks like I’ve arrived late at this party. Still, I might as well share what I’ve brought!

    This works by treating the FALSE/TRUE possibilities like bits, and operating on them to assign to each combination of v1, v2, and v3 a unique integer between 1 and 8 (much like chmod can represent permission bits on *NIX systems). The integer is then used as an index to select the appropriate element of a vector of textual descriptors.

    (For the demonstration, I’ve used just three columns, but this approach scales up nicely.)

    # CONSTRUCT VECTOR OF DESCRIPTIONS
    description <- c("None", "v1", "v2", "v1 and v2",
                     "v3", "v1 and v3", "v2 and v3", "All")
    
    # DEFINE DESCRIPTION FUNCTION
    getDescription <- function(X) {
        index <- 1 + sum(X*c(1,2,4))
        description[index]
    }
    
    # TRY IT OUT ON ALL COMBOS OF v1, v2, and v3
    df <- expand.grid(v1=c(FALSE, TRUE),
                      v2=c(FALSE, TRUE),
                      v3=c(FALSE, TRUE))
    df$description <- apply(df, 1, getDescription)
    
    # YEP, IT WORKS.
    df
    #      v1    v2    v3 description
    # 1 FALSE FALSE FALSE        None
    # 2  TRUE FALSE FALSE          v1
    # 3 FALSE  TRUE FALSE          v2
    # 4  TRUE  TRUE FALSE   v1 and v2
    # 5 FALSE FALSE  TRUE          v3
    # 6  TRUE FALSE  TRUE   v1 and v3
    # 7 FALSE  TRUE  TRUE   v2 and v3
    # 8  TRUE  TRUE  TRUE         All
    
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