I have a dataframe with numerical columns. For each column I would like calculate quantile information and assign each row to one of them. I tried to use the qcut() method to return a list of bins but instead ended up calculating the bins individually. What I thought might exist but I couldn’t find it would be a method like df.to_quintile(num of quantiles). This is what I came up with but I am wondering if there is a more succint/pandas way of doing this.
import pandas as pd
#create a dataframe
df = pd.DataFrame(randn(10, 4), columns=['A', 'B', 'C', 'D'])
def quintile(df, column):
"""
calculate quintiles and assign each sample/column to a quintile
"""
#calculate the quintiles using pandas .quantile() here
quintiles = [df[column].quantile(value) for value in [0.0,0.2,0.4,0.6,0.8]]
quintiles.reverse() #reversing makes the next loop simpler
#function to check membership in quintile to be used with pandas apply
def check_quintile(x, quintiles=quintiles):
for num,level in enumerate(quintiles):
#print number, level, level[1]
if x >= level:
print x, num
return num+1
df[column] = df[column].apply(check_quintile)
quintile(df,'A')
thanks,
zach cp
EDIT: After seeing DSMs answer the function can be written much simpler (below). Man, thats sweet.
def quantile(column, quantile=5):
q = qcut(column, quantile)
return len(q.levels)- q.labels
df.apply(quantile)
#or
df['A'].apply(quantile)
I think using the
labelsstored inside theCategoricalobject returned byqcutcan make this a lot simpler. For example:or to match your code: