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Home/ Questions/Q 8449159
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T10:37:46+00:00 2026-06-10T10:37:46+00:00

I have a DataGrid view that fill it’s content by a list in run

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I have a DataGrid view that fill it’s content by a list in run time.
I want to change (For example) cell value in row:2 and column:3.

How can I do this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T10:37:48+00:00Added an answer on June 10, 2026 at 10:37 am

    It’s not that complicated.

    You need helper functions;

    public static T GetVisualChild<T>(Visual parent) where T : Visual
    {
        T child = default(T);
        int numVisuals = VisualTreeHelper.GetChildrenCount(parent);
        for (int i = 0; i < numVisuals; i++)
        {
            Visual v = (Visual)VisualTreeHelper.GetChild(parent, i);
            child = v as T;
            if (child == null)
            {
                child = GetVisualChild<T>(v);
            }
           if (child != null)
           {
               break;
           }
       }
           return child;
    }
    
    public static DataGridRow GetSelectedRow(this DataGrid grid)
    {
        return (DataGridRow)grid.ItemContainerGenerator.ContainerFromItem(grid.SelectedItem);
    }
    public static DataGridRow GetRow(this DataGrid grid, int index)
    {
        DataGridRow row = (DataGridRow)grid.ItemContainerGenerator.ContainerFromIndex(index);
        if (row == null)
        {
            // May be virtualized, bring into view and try again.
            grid.UpdateLayout();
            grid.ScrollIntoView(grid.Items[index]);
            row = (DataGridRow)grid.ItemContainerGenerator.ContainerFromIndex(index);
        }
        return row;
    }
    
    public static DataGridCell GetCell(this DataGrid grid, DataGridRow row, int column)
    {
        if (row != null)
        {
            DataGridCellsPresenter presenter = GetVisualChild<DataGridCellsPresenter>(row);
    
            if (presenter == null)
            {
                grid.ScrollIntoView(row, grid.Columns[column]);
                presenter = GetVisualChild<DataGridCellsPresenter>(row);
            }
    
            DataGridCell cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(column);
            return cell;
        }
        return null;
    }
    
    public static DataGridCell GetCell(this DataGrid grid, int row, int column)
    {
        DataGridRow rowContainer = grid.GetRow(row);
        return grid.GetCell(rowContainer, column);
    }
    

    Use yourDataGrid.GetCell(5, 3).Content = “whatever you want”;

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