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Home/ Questions/Q 6002303
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T00:57:31+00:00 2026-05-23T00:57:31+00:00

I have a dataset with 10 columns. The first column is an unique identifier.

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I have a dataset with 10 columns. The first column is an unique identifier. The 9 other columns are related attributes. For now, let’s just say they are integers. If needed, the data could easily be pivoted to a key-value.

Ex:

id|attr1|attr2|attr3|...
a |  2  |  5  |  7  |...
b |  3  |  1  |null |...
c |  2  |null |null |...
d |  1  |  2  |  5  |...
e |  2  |  1  |  3  |...

I’m essentially looking for the most frequent combinations of any length with at least a pair. So my output for this would be:

unq   | frequency
1,2   | 2
1,3   | 2
1,5   | 1
2,3   | 1
2,5   | 2
2,7   | 1
1,2,3 | 1
1,2,5 | 1
2,5,7 | 1

(did this manually – so hopefully there are no errors) – the order of the paring doesn’t matter. 2,5,7 = 5,2,7 = 7,5,2 etc.

Any thoughts? I am open to different tools. I have access to R, excel, sql server, mysql, etc.

Excel is preferred but not required!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T00:57:32+00:00Added an answer on May 23, 2026 at 12:57 am

    Here is a solution in R:

    Recreate the data

    x <- data.frame(
        id = letters[1:5],
        attr1 = c(2,3,2,1,2),
        attr2 = c(5,1,NA,2,1),
        attr3 = c(7,NA,NA,5,3))
    x
    
      id attr1 attr2 attr3
    1  a     2     5     7
    2  b     3     1    NA
    3  c     2    NA    NA
    4  d     1     2     5
    5  e     2     1     3
    

    Create a function to list all the combinations

    make_combinations <- function(data, size){
      t1 <- apply(data[, -1], 1, function(data)unname(sort(data)))
      t2 <- lapply(t1, function(xt){if(length(xt)>=size){combn(xt, size)}})
      t3 <- sapply(t2[!is.na(t2)], 
          function(chunk){if(!is.null(chunk))apply(chunk, 2, function(x)paste(x, collapse=","))})
      t4 <- unlist(t3)
      t4
    }
    

    Create a second function to count the combinations

    count_combinations <- function(data, nn=2:3){
      tmp <- unlist(lapply(nn, function(n)make_combinations(data, n)))
      sort(table(tmp), decreasing=TRUE)
    }  
    

    The results:

    count_combinations(x, 2:3)
    
    
      1,2   1,3   2,5 1,2,3 1,2,5   1,5   2,3 2,5,7   2,7   5,7 
        2     2     2     1     1     1     1     1     1     1 
    
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