Question

I have a date string in my XML file as

<DateTime>20120105T103030-0600</DateTime>

I want to change this using XSLT to

<date>20120105</date>
<time>103030</time>

Could any one help me split out the DateTime element to date and time using XSL. Thanks

Answer 1

Some time ago I had a similar problem:

  <xsl:template name="FormatDate">
    <xsl:param name="DateTime" />
    <date>
      <xsl:value-of select="substring($DateTime,1,8)" />
    </date>
    <time>
      <xsl:value-of select="substring($DateTime,10,6)" />
    </time>
  </xsl:template>

Usage:

<xsl:call-template name="FormatDate">
  <xsl:with-param name="DateTime" select="LastWriteTime" />
</xsl:call-template>

Please note that I don’t care for the timezone!