Question

I have a DB (quartos) created with the following structure:

id_quarto  tipo_quarto  vista_quarto |
a      Single   Mar | 
b      Single   Mar |
c      Single   Mar | 
d      Single   Serra |

I want it to return the results of id_quarto, when tipo_quarto=Single and vista_quarto=Mar which values come from a form.

So i write the following:

$strSQL = "
SELECT id_quarto 
FROM quartos 
WHERE tipo_quarto='". $_POST['tipo_quarto'] ."' 
    AND vista_quarto='". $_POST['vista_quarto'] ."'";
$rs = mysql_query($strSQL);
$row = mysql_fetch_array($rs);

Then i loop it and write in a table as followed:

while($row = mysql_fetch_array($rs)) {
<?
<table border="1">
     <tr align="left">
         <td width="75"><?php echo $row['id_quarto']; ?></td>
     </tr>
</table>

The problem here is that it does not return the id_quarto=a , only b and c. Why is that and what can i do to fix it?

Thanks.

Answer 1

You have extra $row = mysql_fetch_array($rs); just after mysql_query($strSQL);. Then in while loop you read $row again (second row in resultset).
So your code will look

$strSQL = "SELECT id_quarto FROM quartos 
  WHERE tipo_quarto='". $_POST['tipo_quarto'] ."' 
  AND vista_quarto='". $_POST['vista_quarto'] ."'";
$rs = mysql_query($strSQL);
// $row = mysql_fetch_array($rs); Don't need this line!!!
while($row = mysql_fetch_array($rs)) 
{
   // output ....
}

Also, it always makes sense to add code for handling mysql errors.