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Home/ Questions/Q 4036726
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T12:15:31+00:00 2026-05-20T12:15:31+00:00

I have a DD class template<typename T> class DD : public IEnumerable<T> { typedef

  • 0

I have a DD class

template<typename T>
class DD
: public IEnumerable<T>
{
    typedef IEnumerable<T> Super;
    typedef std::set<T*> Container;

And a method

template<typename T>
bool DD<T>::Enumerator::Move()
{
    if(!mIt.get()) 
       mIt.reset(
          new Container::iterator( <-----
            mContainer.GetContainer().begin()
          )
       );
       ... 
}

When I compile the class, I got error: expected type-specifier.
What’s wrong with the Container::iterator()?

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  1. Editorial Team
    Editorial Team
    2026-05-20T12:15:32+00:00Added an answer on May 20, 2026 at 12:15 pm

    Try:

    new typename Container::iterator
    

    When you are in a C++ template, the compiler doesn’t know whether Container::iterator is a type or something else. So you need to explicitly say that its a type.

    On another note, creating an iterator with new is almost certainly wrong.

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