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Home/ Questions/Q 8406255
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T23:03:36+00:00 2026-06-09T23:03:36+00:00

I have a def function looks like: def update(marks, num, mark, column): lines =

  • 0

I have a def function looks like:

def update(marks, num, mark, column):
    lines = [l for l in marks]
    for row in range(len(all_marks)):
        if all_marks[row][0] == num:
            lines[row][column] = mark
        elif lines[row][column] != '':
            print num + ' already has a value in column - update ignored.'

and raw_input function inside another def function looks like:

result1 = raw_input('Enter results file: ')
num = raw_input('Student number (empty to finish): ')

if len(snumber) == 0:
    print
    print
    print 'finished'
    print
    print
    return interact()

 else:
    pass

 column2 = raw_input('Enter column: ')
 newresult1 = raw_input('New result: ')

 try:
     print update(result1, snumber, newresult1, column2)

 except IOError:
    print 'Try again'

The third line from the bottom supposed to print def update(marks, num, mark, column) but it keeps returning none.

Sorry, the codes are a bit messy.
Can anyone let me know what I have done wrong?

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-09T23:03:38+00:00Added an answer on June 9, 2026 at 11:03 pm

    Your update function doesn’t look like it returns anything. You need to explicitly return something or there won’t be a return value.

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