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Home/ Questions/Q 635989
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T20:27:58+00:00 2026-05-13T20:27:58+00:00

I have a dendrogram given to me as images. Since it is not very

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I have a dendrogram given to me as images. Since it is not very large, I can construct it “by hand” into an R object.

So my question is how do I manually create a dendrogram (or “hclust”) object when all I have is the dendrogram image?

I see that there is a function called “as.dendrogram” But I wasn’t able to find an example on how to use it.

(p.s: This post is following my question from here)

Many thanks,
Tal

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  1. Editorial Team
    Editorial Team
    2026-05-13T20:27:58+00:00Added an answer on May 13, 2026 at 8:27 pm

    I think you are better of creating an hclust object, and then converting it to a dendrogram using as.dendrogram, then trying to create a dendrogram directly. Look at the ?hclust help page to see the meaning of the elements of an hclust object.

    Here is a simple example with four leaves A, B, C, and D, combining first A-B, then C-D, and finally AB-CD:

    a <- list()  # initialize empty object
    # define merging pattern: 
    #    negative numbers are leaves, 
    #    positive are merged clusters (defined by row number in $merge)
    a$merge <- matrix(c(-1, -2,
                        -3, -4,
                         1,  2), nc=2, byrow=TRUE ) 
    a$height <- c(1, 1.5, 3)    # define merge heights
    a$order <- 1:4              # order of leaves(trivial if hand-entered)
    a$labels <- LETTERS[1:4]    # labels of leaves
    class(a) <- "hclust"        # make it an hclust object
    plot(a)                     # look at the result   
    
    #convert to a dendrogram object if needed
    ad <- as.dendrogram(a)
    
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