Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6029323
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T04:52:10+00:00 2026-05-23T04:52:10+00:00

I have a dictionary dict2 which I want to iter through and remove all

  • 0

I have a dictionary dict2 which I want to iter through and remove all entries that contain certain ID numbers in idlist. dict2[x] is a list of lists (see example dict2 below). This is the code I have written so far, however it does not remove all instances of the IDs (entry[1]) that are in the idlist. Any help?

dict2 = {G1:[[A, '123456', C, D], [A, '654321', C, D], [A, '456123', C, D], [A, '321654', C, D]]}

idlist = ['123456','456123','321654']
for x in dict2.keys():
    for entry in dict2[x]:
        if entry[1] in idlist:
            dict2[x].remove(entry)
        if dict2[x] == []:
            del dict2[x]

dict2 should end up looking like this :

dict2 = {G1:[[A, '654321', C, D]]}
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-23T04:52:11+00:00Added an answer on May 23, 2026 at 4:52 am

    Try a cleaner version perhaps?

    for k in dict2.keys():
        dict2[k] = [x for x in dict2[k] if x[1] not in idlist]
        if not dict2[k]:
            del dict2[k]
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

If I have a dictionary, and I want to remove the entries in which
I have a Dictionary<string, someobject> . EDIT: It was pointed out to me, that
I have a Dictionary where I hold data for movieclips, and I want the
I have a dictionary that I normally access with a key, so I need
I have used AutoCompleteBox usercontrol. I have a dictionary of type Dictionary<int,string> which contains
I want to write a container class that acts like a dictionary (actually derives
I have a list which has items that are either dict s or something
I have a dictionary, lets call it myDict , in Python that contains a
I have a dictionary which store a string as the key, and an integer
I have a dictionary/list balance_sign_dict from which I need to retrieve 2 values based

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.