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Home/ Questions/Q 6332373
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T18:15:06+00:00 2026-05-24T18:15:06+00:00

I have a dictionary of the type: IDictionary<foo, IEnumerable<bar>> my_dictionary bar class looks like

  • 0

I have a dictionary of the type:

IDictionary<foo, IEnumerable<bar>> my_dictionary

bar class looks like this:

class bar
{
    public bool IsValid {get; set;} 
}

How can I create another dictionary with only those items that have IsValid = true.

I tried this:

my_dictionary.ToDictionary( p=> p.Key,
                            p=> p.Value.Where (x => x.IsValid));

The problem with above code is that this creates a key with empty enumerable, if all the elements for that key were IsValid = false.

for example:

my_dictionar[foo1] = new List<bar> { new bar {IsValid = false}, new bar {IsValid = false}, new bar {IsValid = false}};
my_dictionary[foo2] = new List<bar> {new bar {IsValid = true} , new bar{IsValid = false};
var new_dict = my_dictionary.ToDictionary( p=> p.Key,
                            p=> p.Value.Where (x => x.IsValid));
// Expected new_dict should contain only foo2 with a list of 1 bar item.
// actual is a new_dict with foo1 with 0 items, and foo2 with 1 item.

How do I get my expected.

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  1. Editorial Team
    Editorial Team
    2026-05-24T18:15:09+00:00Added an answer on May 24, 2026 at 6:15 pm

    Something like this?

    my_dictionary
        .Where(p=> p.Value.Any(x => x.IsValid))
        .ToDictionary( p=> p.Key,
                       p=> p.Value.Where (x => x.IsValid));
    

    That will only include items where at least one of the values IsValid.

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