Question

I have a dictionary that looks like the below.

For the keys ‘10000ag2′ and 10000ag1’, what is the the most efficient means to find out which key has the last_event with the maximum date?

{'10000ag2': 
    {'last_view': datetime.datetime(2012, 4, 24, 8, 27, 30),
     'last_event': datetime.datetime(2012, 4, 24, 8, 28, 30),
     'last_prid': '300'},
 '10000ag1':
    {'last_view': datetime.datetime(2012, 4, 24, 8, 27, 30),
     'last_event': datetime.datetime(2012, 4, 24, 8, 28, 30),
     'last_prid': '300'}}

I expect a list of e.g. 20 top level keys.

thanks

Answer 1

max(my_dict.items(), key=lambda x: x[1]['last_event'])[0]