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Home/ Questions/Q 6201987
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T04:39:04+00:00 2026-05-24T04:39:04+00:00

I have a dictionary with 46,000 key:value pairs where each key has a 3

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I have a dictionary with 46,000 key:value pairs where each key has a 3 item list as values:

my dict = {key1: ['A', 'B', 'C'], key2: ['B', 'A', 'G'], key3: ['Z', 'H', 'I']......}

I have a list with hundreds of values:

L1 = ['A', 'A', 'B', 'D', ......]

How do I iterate through the list L1 and for each item in L1, match each dictionary value where value[0] matches the list item? I then wish to perform other operations on value[1] and value[2] of the dictionary only on those key:value pairs where a list item matched value[0] in the dictionary.

In the above example, the first item in L1 – ‘A’ would match only key1: ['A', 'B', 'C'].

I can’t seem to figure out a way to do this? Thanks for the help!

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  1. Editorial Team
    Editorial Team
    2026-05-24T04:39:05+00:00Added an answer on May 24, 2026 at 4:39 am

    Without any shortcuts, you could write something like this:

    #!/usr/bin/env python
    
    d = {
        'key1' : ['A', 'B', 'C'], 
        'key2' : ['B', 'A', 'G'], 
        'key3' : ['Z', 'H', 'I']
    }
    
    l = ['A', 'A', 'B', 'D']
    
    uniq_l = set(l) # you don't need to check duplicates twice
    
    for key, value in d.items():
        if value[0] in uniq_l:
            print "Match", key, value
    
    # Output:
    # Match key2 ['B', 'A', 'G']
    # Match key1 ['A', 'B', 'C']
    
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