Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 330345
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 12, 20262026-05-12T09:40:21+00:00 2026-05-12T09:40:21+00:00

I have a directed graph for all kinds of available address formats in Java,

  • 0

I have a directed graph for all kinds of available address formats in Java, which includes cycles. I want to store user Address which is a span of this graph in addition to the above template. My graph is obtained from the XML below:

<address>
    <city start="true">
        <minicity />
        <street />
        <square />
    </city>
    <minicity>
        <street />
        <alley />
        <square />
    </minicity>
    <street>
        <street />
        <alley />
        <blibd />
    </street>
    <square>
        <street />
        <alley />
        <blibd />
    </square>
    <alley final="true">
        <alley />
        <blibd />
        <plaque />
    </alley>
    <blibd final="true">
        <alley />
        <blibd />
        <plaque />
    </blibd>
    <plaque final="true">
        <stage />
        <unit />
    </plaque>
    <stage final="true">
        <unit />
    </stage>
    <unit final="true">
    </unit>
</address>

As you can see the street node of the graph has a cycle above itself. A sample of the user address would look like this:

city:a street:b street:c street:d alley:f

My question is:
What is the best way to store the user’s address graph? I have the above template graph and want to know whether it would be better to save the user graph within this template or outside in a different structure.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-12T09:40:22+00:00Added an answer on May 12, 2026 at 9:40 am

    An adjacency matrix is a standard way of representing a graph. In your case each element of the matrix could be supplemented with the node category (city, etc).

    A user’s address could be derived by storing a separate reference to the inner most node of a given address and tracing outwards to the city level to construct the address.

    I personally would probably opt for a more structured approach than a generic graph though, creating business objects like City, Street, etc, and therefore enforcing the structure of the address; e.g.

    public interface Residence {
      int getNumber();
      Street getStreet();
    }
    
    public interface Street {
      City getCity();
    }
    
    public interface City {
      Country getAddress();
    }
    

    To display an address given a Residence I simply walk the object graph; e.g.

    Residence r = ...
    System.err.println(String.format("%d %s %s %s", r.getNumber(), r.getStreet(), r.getStreet().getCity(), r.getStreet().getCity().getCountry()));
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 271k
  • Answers 272k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer If the word is "classic", then I'd say the collection… May 13, 2026 at 1:50 pm
  • Editorial Team
    Editorial Team added an answer Why don't you use the TTLauncherView? May 13, 2026 at 1:50 pm
  • Editorial Team
    Editorial Team added an answer You could use some(), a Mozilla extension which has been… May 13, 2026 at 1:50 pm

Related Questions

I have a set of students (referred to as items in the title for
Having seen some suggestions for graphs, I wonder what's the optimum for my problem.
In the past, I've written Linq to SQL queries that haven't performed well. Using
I have a graph with an s and t vertex that I need to

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.