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Home/ Questions/Q 8072371
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T13:59:49+00:00 2026-06-05T13:59:49+00:00

I have a directory structure like this: –bin/ –lib/ –data/ So basically, the executable

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I have a directory structure like this:

--bin/
--lib/
--data/

So basically, the executable script is in bin and it calls the files in lib.. but lib has to communicate with the text files in data

Usually this use to work:
TO read a file in usually i use to do this

file_path =  os.path.join(os.path.dirname(__file__))+ "/../" +"data/"+filename
f = open(file_path,"r")

But, in this instance, if i do:

  print os.path.join(os.path.dirname(__file__))
  returns nothing?

What am i doing wrong..
Thanks

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  1. Editorial Team
    Editorial Team
    2026-06-05T13:59:51+00:00Added an answer on June 5, 2026 at 1:59 pm

    I guess with nothing you mean an empty string? This could only be the case, if __file__ was an empty string in the first place. Did you accidentally overwrite __file__?

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