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Home/ Questions/Q 7933477
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T21:20:46+00:00 2026-06-03T21:20:46+00:00

I have a directory structure like this… dir/ build.py dir2 dir3/ packages.py Now the

  • 0

I have a directory structure like this…

dir/
  build.py
dir2
  dir3/
  packages.py

Now the build.py needs packages.py — and note that dir2 is not a package.

So what’s the best way to get packages.py loaded into build.py (the directory structure can’t be changed)

EDIT

The sys.path.append solution seems good — but there is one thing — I need to use the packages.py file rarely — and keeping a sys.path that includes a directory that is used rarely, but is at the front — is that the best thing?

EDIT II

I think the imp solution is best.

import imp    
packages = imp.load_source('packages', '/path/to/packages.py')

EDIT III

for Python 3.x

Note that imp.load_source and some other function have been deprecated. So you should use the imp.load_module today.

fp, pathname, description = imp.find_module('packages', '/path/to/packages.py')
try:
    mod = imp.load_module('packages', fp, pathname, description)
finally:
    # since we may exit via an exception, close fp explicitly
    if fp:
        fp.close()
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  1. Editorial Team
    Editorial Team
    2026-06-03T21:20:48+00:00Added an answer on June 3, 2026 at 9:20 pm

    You could do:

    sys.path.append('./dir2/dir3')
    import packages
    

    Or better yet:

    sys.path.append(os.path.join(os.path.dirname(__file__), 'dir2/dir3'))
    import packages
    

    Or (taken from here: How to import a module given the full path?)

    import imp    
    packages = imp.load_source('packages', '/path/to/packages.py')
    
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