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Home/ Questions/Q 878895
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T11:50:20+00:00 2026-05-15T11:50:20+00:00

I have a div element, with img element in it. onclick of div i

  • 0

I have a div element, with img element in it.

onclick of div i make one function, and onclick on img – another. but when i click on img it make the first function too, because the img is in div element.
so, i think, that if there were something like isClicked, onclick of div i can just verify, if img is Not clicked …

(i can write a logic, and verify it by so,for example onclick of img i can add a class to somebody… but maybe there is a function for it?)

Thanks

Update:

<div class="left_expended" style="position: relative;">
    Լեզուներ
    <img src="images/new_page.gif" id="new_lang" title="Լեզու ավելացնել" />
</div>

and jquery

$(".left_expended").live('click', function(){
            $(this).addClass("left_collapsed");
            $(this).removeClass("left_expended");
            $(this).next("div .container").slideUp(400);
        });

        $("#new_lang").click(function()
        {
            alert("something");
        });

onclick of img it makes first function too.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T11:50:21+00:00Added an answer on May 15, 2026 at 11:50 am

    You can prevent the click on the <img> from going up to the <div> using event.stopPrpagation(), like this:

    $("#new_lang").click(function(e) {
      alert("something");
      e.stopPropagation();  //don't bubble!
    });
    

    What happens normally is that events bubble, the click on the <img> “bubbles up” to the <div> afterwards…unless you stop it, which is exactly what .stopPropagation() does. This way anything activating your $("div").click(...) is anywhere inside except the image, because a click there wouldn’t go up anymore, which seems to be what you’re after 🙂

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