Question

I have a div that appears when a checkbox is checked, and hides when unchecked. If the form has errors, the page reloads and the div appears hidden even if the checkbox was checked before submission. I can add a call to the onLoad event, but is there a cleaner way to ensure that, after page reload, the div is rendered based on the status of the checkbox?

Css:

#maintenance-window { display: none; }

jQuery:

$("#check-hasMaintenance").click(function() {
    $(this).is(":checked") ? $('#maintenance-window').show("fast") : $('#maintenance-window').hide("fast")
});

HTML:

<input type="checkbox" value="1" id="check-hasMaintenance">
<div id="maintenance-window">
    Stuff
</div>

Answer 1

Option 1

Ensure div is shown based on check box when the page loads:

$(document).ready(function() {
     // Modified for readability - inline if is fine.
     if($("#check-hasMaintenance").is(":checked"))
         $('#maintenance-window').show("fast")
     else
         $('#maintenance-window').hide("fast");
});

Simplified hide/show code:

$("#check-hasMaintenance").click(function() {
    $('#maintenance-window').toggle('fast');
});

Option 2

A short-hand version like this should work as well:

$(document).ready(function() {
    $('#maintenance-window').toggle($("#check-hasMaintenance").is(":checked"));
});

$("#check-hasMaintenance").click(function() {
    $('#maintenance-window').toggle('fast');
});