Question

I have a div with the id of “secondHeader” and I want to replace that entire div with another div with the same id of “secondHeader” but instead of replacing it , it just adds the loaded div inside the first one.

$("#secondHeader").load("/logged-in-content.html #secondHeader");

This is what happens…

<div id="secondHeader"><div id="secondHeader"></div></div>

What I want to happen is the secondHeader div from the ajax load to totally replace the secondHeader in the initial page.

I know it sounds dumb, but here’s what I’m trying to accomplish…When a user is not logged in, they see a non-logged in header. I am using ajax to allow the person to log into the site and I want to replace the non-logged in header with the logged in one via ajax.

I have tried everything I know such as…

$("#secondHeader").replaceWith($("#secondHeader").load("/logged-in-content.html #secondHeader"));

…and using .remove() before hand…

Any ideas?

Answer 1

I think the best way is to use get instead of load. In your case you can do like this:

$.get("/logged-in-content.html #secondHeader", function(data) {
     $("#secondHeader").replaceWith(data);
});

[Edit: removed a paren]

Update:
If /logged-in-content.html has more than just the code you need, you can wrap the returning data in another jQuery object and use .find() to extract the container.
Try this:

$(“#secondHeader”).replaceWith($(data).find(“#secondHeader”));