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Home/ Questions/Q 3353756
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T02:11:24+00:00 2026-05-18T02:11:24+00:00

I have a Django model that looks something like this: class Person(models.Model): name =

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I have a Django model that looks something like this:

class Person(models.Model):

    name = models.CharField(max_length=32)
    place = models.ForeignKey(Place, related_name='people')
    approved = models.BooleanField()
    objects = PersonManager()

    @models.permalink
    def get_absolute_url(self):
        return('deal_details', (), {
            'person_slug': slugify(self.name),
        })

As you could see, I already have an absolute URL for the object. However, I want to create a difficult-to-guess URL to keep track of the approval process of the object. Anyone done something similar and/or have any suggestions on how I should proceed?

My first thought was creating a model field like obfuscated_key that is generated randomly via the save function of the model. Then the URL would look something like /people/status/<id>/<obfuscated_key>/. But perhaps there’s a better way to go about this?

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  1. Editorial Team
    Editorial Team
    2026-05-18T02:11:25+00:00Added an answer on May 18, 2026 at 2:11 am

    A good way to do this would be to hash the object’s ID with the installation’s secret key (from settings.py). This is what the password reset email form does – there’s some useful code in django.contrib.auth.tokens – and, in the very latest SVN versions, django.contrib.auth.crypto.

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