Question

I have a Django model which I need to hold a callable (in this case a reference to another model) to store it along with some “conditions” which should later be applied to the model.

My approach was like so:

MODEL_CHOICES = (
     (django.contrib.auth.models.User, 'User'),
     [some more]
     )
class Model:
     chosen_model = models.IntegerField(choices=MODEL_CHOICES)
     conditions = models.TextField()

Conditions would look something like this:

{'status': 1, [some other]}

But obviously

django.contrib.auth.models.User

is not a valid integer.

What I try to achive is the following:
Call

chosen_model.objects.filter(**conditions)

in a view.
Is this even possible? If yes, what kind of Field do I need to store a reference to a model?

Thank you very much!

Answer 1

I would suggest you use the ContentType model here.

from django.contrib.contenttypes.models import ContentType

class YourModel:
     chosen_model = models.ForeignKey(ContentType)
     conditions = models.TextField()