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Home/ Questions/Q 8771525
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T17:48:38+00:00 2026-06-13T17:48:38+00:00

I have a Django site that uses item names to create viewer-friendly URLs. For

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I have a Django site that uses item names to create viewer-friendly URLs. For instance:

/item/DeluxeWidget/

I have an item that has an ampersand in the name:

/item/Red & Blue Widget/

The ampersand throws things off. If I use {{ widget.name|fix_ampersands }}, the ampersand will be escaped as & but it still isn’t picked up in the URL pattern:

url(r"^widget/(?P<name>[0-9a-zA-Z&,. -]+)/$", 'site.views.widget' ),

In the view I use the captured name to do

Widget.objects.get(name=name)

What’s the right combination of escaping, patterns, or filters to handle an ampersand in a URL? I also expect to run into names with apostrophes in them. Is there anything I should do to handle those too?

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  1. Editorial Team
    Editorial Team
    2026-06-13T17:48:39+00:00Added an answer on June 13, 2026 at 5:48 pm

    Consider using a SlugField which can automatically be filled with a cleaned up version of another field suitable for use in URLs.

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