Question

I have a django template page, and want a link from this page, containing current URL, for example, I am on /article/11 and want link to /article/11/remove
I tried the following construction:

<a href="{{ request.path }}remove">Remove article</a>

But I get link to /article/remove instead of /article/11/remove
However when I change it to

<a href="{{ request.path }}">

I get link to /article/11

How can I get URL not trimmed?

Answer 1

I don’t see why it doesn’t point you to /article/11remove, which is what it sounds like it should do, but either way, you’re missing a slash. Try <a href="{{ request.path }}/remove"> instead.

However, that’s really not the right way to do it. You shouldbe using {% url ‘name_of_remove_view’ %} to get the url, not assuming it’s going to be wherever you are plus /remove.

Edit: In that case, your problem is probably that {{ request.path }} is not outputting anything at all. That would explain why just having “remove” would take you to /article/remove, and having “” would take you to where you currently are, due to the way that relative URLs work. You might want to make sure that you have a request object at all in your template environment.