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Home/ Questions/Q 7401635
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T04:31:33+00:00 2026-05-29T04:31:33+00:00

I have a DLL which exports a function: __declspec(dllexport) void __stdcall MyEntryPoint(char* params) {

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I have a DLL which exports a function:

__declspec(dllexport) 
void __stdcall MyEntryPoint(char* params)
{
    MessageBoxA("MyEntryPoint",params,0,0);
}

How can I use rundll32.exe to load my DLL and call MyEntryPoint()?

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  1. Editorial Team
    Editorial Team
    2026-05-29T04:31:34+00:00Added an answer on May 29, 2026 at 4:31 am

    You need to define a function with a very specific signature in order for it to be callable by rundll32. Have a look at this blog entry for information, which includes details on how and why you may get crashes.

    Also, take a look at this answer to a similar question, where the signature of the function is detailed.

    Essentially for your function to be callable safely it would need to be defined as something like:

    void CALLBACK MyEntryPoint(HWND hwnd, HINSTANCE hinst, LPSTR pszCmdLine, int nCmdShow);
    

    or

    void CALLBACK MyEntryPointW(HWND hwnd, HINSTANCE hinst, LPWSTR pszCmdLine, int nCmdShow);
    

    Anything else will corrupt the stack and may (or may not) cause a crash. I think that in later versions of Windows, rundll will first look for the MyEntryPointW function, and if found call that – the difference is in the Unicode pszCmdLine parameter.

    For more information on how to use rundll32, have a look at MSDN, which details what to expect for each of the parameters, etc.

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