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Home/ Questions/Q 828951
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T03:48:22+00:00 2026-05-15T03:48:22+00:00

I have a double value that equals 1.212E+25 When I throw it out to

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I have a double value that equals 1.212E+25

When I throw it out to text I do myVar.ToString(“0000000000000000000000”)

The problem is even if I do myVar++ 3 or 4 times the value seems to stay the same.

Why is that?

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  1. Editorial Team
    Editorial Team
    2026-05-15T03:48:23+00:00Added an answer on May 15, 2026 at 3:48 am

    double (Double) holds about 16 digits of precision and long (Int64) about 18 digits.

    Neither of these appear to have sufficient precision for your needs.

    However decimal (Decimal) holds up to 30 digits of precision. Although this appears to be great enough for your needs I’d recommend caution in case your requirement grows even larger. In that case you may need a third party numeric library.

    Related StackOverflow entries are:
    How can I represent a very large integer in .NET?
    Big integers in C#

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