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Home/ Questions/Q 7604125
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T23:49:49+00:00 2026-05-30T23:49:49+00:00

I have a dynamic list of categories, which is retrieved from mySQL. When the

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I have a dynamic list of categories, which is retrieved from mySQL. When the user is clicking on a category, it loads images for that specific category from the DB. This is the function that does it:

function getImages($categoryID)
{
return json_encode(select("SELECT * FROM images WHERE categoryID=$categoryID"));
}

Now I also want to retrieve also the category name again from the “categories” table (to include the name of the selected category in other part of the page). I tried to do this:

function getImages($categoryID)
{
return json_encode(select(
        "SELECT categories.categoryName, images.imageFileName, images.imageHeader 
        FROM images JOIN categories 
        ON categories.categoryID = images.categoryID 
        WHERE categoryID=$categoryID"));
}

but that didn’t work, now I don’t even get the images.

How can it be done?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T23:49:50+00:00Added an answer on May 30, 2026 at 11:49 pm

    In your WHERE clause, categoryID is ambiguous.

    WHERE categoryID=$categoryID
    

    Since you have two tables with categoryID, you need to identify which one the WHERE should be looking at.

    WHERE categories.categoryID=$categoryID
    

    To make life easier for yourself, you might want to consider aliasing your tables, like this:

    SELECT c.categoryName, i.imageFileName, i.imageHeader 
    FROM images i
    JOIN categories c ON c.categoryID = i.categoryID 
    WHERE c.categoryID=$categoryID
    

    Also, which language are you developing in? If this is a web app, you might want to consider escaping $categoryID to protect against SQL injection.

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