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Home/ Questions/Q 8689813
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T23:44:53+00:00 2026-06-12T23:44:53+00:00

I have a fairly large codebase with several directories and files and I would

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I have a fairly large codebase with several directories and files and I would like to check out a view or have a view as of a given date (Septermber 12th). I am manually checking file histories and doing ct get -to someOtherDir/FileName FilenName@@/main/## and this is extremely painful. I wonder if there is a way to do a checkout and load everything as of a particular day at once?

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  1. Editorial Team
    Editorial Team
    2026-06-12T23:44:55+00:00Added an answer on June 12, 2026 at 11:44 pm

    The easiest way is to make a separate dynamic view, with a config spec including a time-based selection rule (or time rule for short, see cleartool man config_spec).

    See as an example “ClearCase : Loading Older Version of a specific Directory?“.

    Since you want to checkout files, you need to complete your selection rule by a mkbranch directive.

    element * .../aBranch/LATEST
    element /aVob/myComponent/mySubDirectory/... .../aParentBranch/LATEST -time dd-Month-yyyy -mkbranch aBranch
    element * /main/LATEST
    

    If those elements were all created on ‘aParentBranch‘, they will be selected at the right date, and branched into a new branch ‘aBranch‘ when checked out.

    If those elements were all on /main, you can switch the last two selection rules into:

    element * /main/LATEST -time dd-Month-yyyy -mkbranch aBranch 
    

    From the man page:

    -time date-time
    

    Modifies the meaning of the special version label LATEST:
    the rule selects from a branch the last version that was created before a particular time.

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