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Home/ Questions/Q 3498748
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T12:31:39+00:00 2026-05-18T12:31:39+00:00

I have a few JavaScript functions that all look similar to me. but behave

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I have a few JavaScript functions that all look similar to me. but behave differently to how I want them to.

I would like another element to be updated with some text when the value of the input has been evaluated. However for code re-useability I would like to pass the element to be updated to the function, but when I do this the keyup() event will not fire when text is typed into the input box.

Why is this?

Here is the one that works, but I have so specify the element to be updated explicitly.

Keyup Working

$(function(){ 
     $("#form1").keyup(function(){
         var val = $(this).val();
         if(val.length < 5){
             $("#inputFeedback").html("Less then 5 chars");
         }else{
             $("#inputFeedback").html("More then 5 Chars!");
     }
});

Here is what I would like to do but the keyup() event will not work on.

Keyup Not working

var validate = function(feedback){
   var val = $(this).val();
   if(val.length < 5){
       $(feedback).html("Less then 5 chars");
   }else{
       $(feedback).html("More then 5 Chars!");
   }
}


$(function(){
    $("#form1").keyup(validate($("#inputFeedback")));
});

Note: I have also tried as arguments $(this) and "#inputfeedback" to no avail!

I have also tried to use classical JavaScript function foo(bar){ ... } type functions but this has the same effect as the last example above.

I am sure it is something I am not doing right or understanding here but after a good few hours of searching and reading I can’t find anything to help me with this one!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T12:31:39+00:00Added an answer on May 18, 2026 at 12:31 pm

    You definitely can’t do callbacks like that:

    http://docs.jquery.com/How_jQuery_Works#Wrong

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