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Home/ Questions/Q 6356147
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T22:54:28+00:00 2026-05-24T22:54:28+00:00

i have a few php vars: $test = 12345; $test1 = test1; $test2 =

  • 0

i have a few php vars:

$test = 12345;
$test1 = "test1";
$test2 = "test2";

and i have a jquery function:

onlike:function(response){
    $('input#helpdiv').trigger('click');    
}

what i want is to pass those php vars through a jquery post to another test.php file.

I was thinking on something like this:

var test = <?php echo $test; ?>; 
var test1 = <?php echo $test1; ?>; 
var test2 = <?php echo $test2; ?>; 

onlike:function(response){
    $('input#helpdiv').trigger('click');
    $.post("test.php", { test, test1, test2 } );
}

and then how do i get them in the test.php? just like $_GET["test"], ...

any ideas on how to put this together?

thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T22:54:29+00:00Added an answer on May 24, 2026 at 10:54 pm
    <script language='javascript'> 
     var test = "<?php echo $test; ?>"; 
      var test1 = "<?php echo $test1; ?>"; 
      var test2 = "<?php echo $test2; ?>"; 
    
      onlike:function(response){
          $('input#helpdiv').trigger('click');
          $.post("test.php", { test:test, test1:test1, test2:test2  } );
            }
     </script>
    

    in test.php you can access them as $_POST[‘test’],$_POST[‘test1’],$_POST[‘test2’]

    EDIT:

    to avoid problems caused by quotes in between the variable values,
    as explained in: how to post and get php vars with jquery?

      var test = "<?php echo json_encode($test); ?>"; 
    

    and the values may be accesed in test.php as

     $test1 = json_decode($_POST['test'])
    
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