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Home/ Questions/Q 8951515
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T13:40:58+00:00 2026-06-15T13:40:58+00:00

I have a few questions about pointers. I have the following struct struct buffer

  • 0

I have a few questions about pointers.

I have the following struct

struct buffer {
    char *ptr;
    char data[DATA_SIZE];
};

and I have the following code

printk("ptrs and what not:  buf=%p, b-ptr=%p,   b-data=%p,    INIT_LOC=%lu\n", buf, buf->ptr, buf->data, INIT_LOC);

if (buf)
    buf->ptr = buf->data + INIT_LOC;

printk("ptrs and what not:  buf=%p, b-ptr=%p,   b-data=%p,    INIT_LOC=%lu\n", buf, buf->ptr, buf->data, INIT_LOC);

The output is the following:

ptrs and what not:  buf=ffff880091ae2000, b-ptr=          (null),   b-data=ffff880091ae2008,    INIT_LOC=10
ptrs and what not:  buf=ffff880091ae2000, b-ptr=ffff880091ae2012,   b-data=ffff880091ae2008,    INIT_LOC=10

questions

1) when adding a number, lets say 2 to a ptr with an address lets say 10001
is the value 10003, or 10001 + 2 * sizeof(X), where x is the type of the ptr.

2) if ptr=10001 is an array of chars in memory, the first character in that array is at location 10001, is the second character at location 10002 or 10009? or what would it be?

3) going to the printout shown above the buf->data has address 2008, i am not sure how adding 10 to it makes it point to 2012.

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-15T13:40:59+00:00Added an answer on June 15, 2026 at 1:40 pm
    1. 10001 + 2 * sizeof(X)
    2. 10002
    3. It’s in hex, 0x2012-0x2008 equals 10 in decimal.
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