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I have a few sets which are like
SET A(1,2,3,11,10) - $30
SET B(2,5,8) - $20
SET C(6) -$25
SET D(6,8) -$30
SET E(7,5) -$20
SET F(5,6,7,8,9,10) -$60
.
.
.
and so on…
All are random,
Now consider sets D,E and F
I want to buy the cheapest combination for a set, SET Q(7,8,6,5)
the answer should be SET D + SET E, not the SET F
Please link… thanks
This problem is called Weighted Set Covering.
You’ll get lots of results searching for that term on Google.