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Home/ Questions/Q 1075109
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T21:13:44+00:00 2026-05-16T21:13:44+00:00

I have a few things going on that need to be done one after

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I have a few things going on that need to be done one after the other, not all methods have callback features so what’s the best way to go about chaining these events together?

I have something like this

Close slider > Delete old content > Append new content > Re-open slider

I’m new to JQuery so this may seem obvious but I appreciate any help!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T21:13:44+00:00Added an answer on May 16, 2026 at 9:13 pm

    You can use queues and explicitly defined queue, but in this case you can just make use of a call back with .slideUp().

    Since animations can be chained to add them to the default queue, you can just chain .slideDown() right after the .slideUp().

    $(sliderSelector).slideUp(function() { 
        // delete and add stuff
    }).slideDown();
    

    jsFiddle example


    If you are using custom slide up and slide down functionality with no call back, then I don’t know if you have automatic queueing functionality added into the chaining either, so you can just create a queue on the fly using .queue():

    $(this).queue(function() {
          // Stuff to do
        // ...
          // Dequeue
        $(this).dequeue; 
    });
    

    So your whole code would be:

        $(this).queue(function() {
            $(this).customUp();
            $(this).dequeue();
        }).queue(function() {
            // Delete & add stuff
            // ...
            $(this).dequeue();
        }).queue(function() {
            $(this).customDown();
            $(this).dequeue();
        });
    

    jsFiddle example

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