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Asked: May 10, 20262026-05-10T21:57:49+00:00 2026-05-10T21:57:49+00:00

I have a file and I don’t know how big it’s going to be

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I have a file and I don’t know how big it’s going to be (it could be quite large, but the size will vary greatly). I want to search the last 10 lines or so to see if any of them match a string. I need to do this as quickly and efficiently as possible and was wondering if there’s anything better than:

s = 'foo' last_bit = fileObj.readlines()[-10:] for line in last_bit:     if line == s:         print 'FOUND' 
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  1. 2026-05-10T21:57:49+00:00Added an answer on May 10, 2026 at 9:57 pm
    # Tail from __future__ import with_statement  find_str = 'FIREFOX'                    # String to find fname = 'g:/autoIt/ActiveWin.log_2'     # File to check  with open(fname, 'r') as f:     f.seek (0, 2)           # Seek @ EOF     fsize = f.tell()        # Get Size     f.seek (max (fsize-1024, 0), 0) # Set pos @ last n chars     lines = f.readlines()       # Read to end  lines = lines[-10:]    # Get last 10 lines  # This returns True if any line is exactly find_str + '\n' print find_str + '\n' in lines  # If you're searching for a substring for line in lines:     if find_str in line:         print True         break 
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