Question

I have a file with this content

  import os
  import sys

  sys.path.append('/home/user/dj/project/')
  sys.path.append('/home/user/dj/')

  os.environ.setdefault("DJANGO_SETTINGS_MODULE", "proj.settings")

  import django.core.handlers.wsgi
  application = django.core.handlers.wsgi.WSGIHandler()

/home/user/dj/proj/ and /home/user/dj/ could be other, unknown values.

I have a bash script to do an installation, and in there I want to execute something to change those lines to this

  import os
  import sys

  sys.path.append('/var/django/proj/')
  sys.path.append('/var/django/')

  os.environ.setdefault("DJANGO_SETTINGS_MODULE", "proj.settings")

  import django.core.handlers.wsgi
  application = django.core.handlers.wsgi.WSGIHandler()

I tried with sed but I had troubles with greediness in regex.

I tried with perl -pi -e s/str1/str2/ but I had troubles because perl repaces all occurences.

EDIT:
To clarify, I want to replace only the values inside the single quotes. i.e:

sys.path.append('foo') with sys.path.append('what I want') and

sys.path.append('bar') with sys.path.append('the second thing I want')

and bar could be different or equal to foo

Answer 1

I finally used this

sed -i "1,/sys.path.append/ {/sys.path.append/i sys.path.append('$HOMEDIR/')\nsys.path.append('/home/$SYS_USER/')
}" $HOMEDIR/wsgi.py

with that carriage return before the }

is the only thing that worked for me.