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Home/ Questions/Q 810633
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T00:55:01+00:00 2026-05-15T00:55:01+00:00

I have a folder called notes, naturally they will be categorized into folders, and

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I have a folder called notes, naturally they will be categorized into folders, and within those folders there will also be sub-folders for sub categories. Now my problem is I have a function that walks through 3 levels of sub directories:

def obtainFiles(path):
      list_of_files = {}
      for element in os.listdir(path):
          # if the element is an html file then..
          if element[-5:] == ".html":
              list_of_files[element] = path + "/" + element
          else: # element is a folder therefore a category
              category = os.path.join(path, element)
              # go through the category dir
              for element_2 in os.listdir(category):
                  dir_level_2 = os.path.join(path,element + "/" + element_2)
                  if element_2[-5:] == ".html":
                      print "- found file: " + element_2
                      # add the file to the list of files
                      list_of_files[element_2] = dir_level_2
                  elif os.path.isdir(element_2):
                      subcategory = dir_level_2
                      # go through the subcategory dir
                      for element_3 in os.listdir(subcategory):
                          subcategory_path = subcategory + "/" + element_3
                        if subcategory_path[-5:] == ".html":
                            print "- found file: " + element_3
                            list_of_files[element_3] = subcategory_path
                        else:
                            for element_4 in os.listdir(subcategory_path):
                                 print "- found file:" + element_4

Note that this is still very much a work in progress. Its very ugly in my eyes…
What I am trying to achieve here is to go through all the folders and sub folders down and put all the file names in a dictionary called “list_of_files”, the name as “key”, and the full path as “value”. The function doesn’t quite work just yet, but was wondering how would one use the os.walk function to do a similar thing?

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T00:55:02+00:00Added an answer on May 15, 2026 at 12:55 am

    Based on your short descriptions, something like this should work:

    list_of_files = {}
    for (dirpath, dirnames, filenames) in os.walk(path):
        for filename in filenames:
            if filename.endswith('.html'): 
                list_of_files[filename] = os.sep.join([dirpath, filename])
    
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