Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8000013
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 4, 20262026-06-04T15:40:18+00:00 2026-06-04T15:40:18+00:00

I have a folder in windows/Linux which has below files test_1a.play test_1AA.play test_1aaa.play test-_1AAAA.play

  • 0

I have a folder in windows/Linux which has below files

test_1a.play
test_1AA.play
test_1aaa.play
test-_1AAAA.play

I am reading files and and storing it But windows and linux gives different order. As my application runs in both platform I need consistent order(Linux order). Any suggestion for fixing this.

File root = new File( path );
File[] list = root.listFiles();
list<File> listofFiles = new ArrayList<File>();
.....
for ( File f : list ) {


...
read and store file in listofFiles
...
}
Collections.sort(listofFiles);

Windows gives me below order

test-_1AAAA.play
test_1a.play
test_1AA.play
test_1aaa.play

Linux gives me below order

test-_1AAAA.play
test_1AA.play
test_1a.play
test_1aaa.play
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-04T15:40:20+00:00Added an answer on June 4, 2026 at 3:40 pm

    You will need to implement your own Comparator<File> since the File.compareTo uses the “systems” order.

    I think (not checked) that Linux uses the “standard” order by file name (case sensitive) so an example implementation could look like this:

    public static void main(String[] args) {
        List<File> files = new ArrayList<File>();
        files.add(new File("test_1a.play"));
        files.add(new File("test_1AA.play"));
        files.add(new File("test_1aaa.play"));
        files.add(new File("test-_1AAAA.play"));
    
        Collections.sort(files, new Comparator<File>() {
            @Override
            public int compare(File o1, File o2) {
                String p1 = o1.getAbsolutePath();
                String p2 = o2.getAbsolutePath();
                return p1.compareTo(p2);
            }
        });
    
        System.out.println(files);
    }
    

    Outputs:

    [test-_1AAAA.play, test_1AA.play, test_1a.play, test_1aaa.play]
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a folder called Etc which has an image I want to use
I have a folder on my remote server that has a few .png files
I have the following situation: There is a windows folder that has been mounted
I am searching for an efficient way to test if files exists which have
I have a project which is built for multiple OSes(Linux and Windows for now,
I have a known shared folder on another Windows PC and i have to
I have folder on which i want to apply security like the current user
We have a folder where our app will be potentially reading, writing and creating/deleting
I have a folder full of 100-odd Access97 files. I need to update them
I have a folder, called files. It's already in the repository. Now, new files

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.